JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

\frac{d}{{dx}}\left[ {{x^x} + {x^a} + {a^x} + {a^a}} \right] = \ldots ,a

is constant

View answer and explanation

Correct option: B

{x^x}(1 + \log x) + a.{x^{a - 1}} + {a^x}\log a

Option B (

{x^x}(1 + \log x) + a.{x^{a - 1}} + {a^x}\log a

) is correct because it is the result of differentiating each term in the given expression with respect to x.

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