The 2nd derivative of $a{\sin ^3}t$ with respect to $a{\cos ^3}t$ at $\,t = \frac{\pi }{4}$

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

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Analyzing +4 | -1

The 2nd derivative of

a{\sin ^3}t

with respect to

a{\cos ^3}t

\,t = \frac{\pi }{4}

View answer and explanation

Correct option: A

\frac{{4\sqrt 2 }}{{3a}}

Option A (

\frac{{4\sqrt 2 }}{{3a}}

) is correct because it is the value obtained after calculating the second derivative and substituting

t = \frac{\pi}{4}

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