JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1

A conducting loop of area

5.0 \mathrm{~cm}^2

is placed in a magnetic field which varies sinusoidally with time as

B=B_0 \sin \omega t

where

B_0=0.20 \mathrm{~T}

and

\omega=300 \mathrm{~s}^{-1}

. The normal to the coil makes an angle of

60^{\circ}

with the field. Find

(a) the maximum emf induced in the coil,

(b) the emf induced at

\tau=(\pi / 900)\text{ s}

and

(c) the emf induced at

t=(\pi / 600) \mathrm{s}

View answer and explanation

Correct option: A

(a)

0.015 \mathrm{~V};

(b)

7.5 \times 10^{-3} \mathrm{~V};

Option A ( (a)

0.015 \mathrm{~V};

(b)

7.5 \times 10^{-3} \mathrm{~V};

(c) zero) is correct because it accurately calculates the maximum induced emf and the emf at the specified times using Faraday's law.

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