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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1
Number real solutions of the equation is ∑k=12019k2∣x2+(k+3)x−k−4∣=0\sum\limits_{{k=1}}^{2019} k^2\left|x^2+(k+3) x-k-4\right|=0
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Correct option: B
1
Option B (1) is correct because the equation simplifies to |x-1|=0, resulting in only one real solution.

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