If $f\left( 4 \right) = 4,f'\left( 4 \right) = 1$, then $\mathop {\lim }\limits_{x \to 4} \frac{{2 - \sqrt {f\left( x \right)} }}{{2 - \sqrt x }}$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

f\left( 4 \right) = 4,f'\left( 4 \right) = 1

, then

\lim\limits_{x \to 4} \frac{{2 - \sqrt {f\left( x \right)} }}{{2 - \sqrt x }}

is equal to

View answer and explanation

Correct option: B

The correct answer is B (1) because applying L'Hopital's rule simplifies the limit to 1.

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