JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

For the function

f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+\ldots+\frac{x^2}{2}+x+1,

f^{\prime}(1)=m f^{\prime}(0),

where

m

is equal to

View answer and explanation

Correct option: C

100

Option C (100) is correct because f'(1) = 100 and f'(0) = 1, so f'(1) = 100f'(0).

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