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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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sin⁡−1x+sin⁡−11x+cos⁡−1x+cos⁡−11x{\sin ^{ - 1}}x + {\sin ^{ - 1}}\frac{1}{x} + {\cos ^{ - 1}}x + {\cos ^{ - 1}}\frac{1}{x} is equal to
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Correct option: A
π\pi
Option A (π\pi) is correct because using the identity sin⁡−1x+cos⁡−1x=π2{\sin ^{ - 1}}x + {\cos ^{ - 1}}x = \frac{\pi }{2}, the expression simplifies to π2+π2=π\frac{\pi }{2} + \frac{\pi }{2} = \pi.

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