JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

The set of values of

p

for which the roots of the equation

3\;{x^2} + 2\;x + p\left( {p - 1} \right) = 0

are of opposite signs is

View answer and explanation

Correct option: B

\left( {0,\;1} \right)

Option B ((0, 1)) is correct because for roots to have opposite signs, the product of roots must be negative, leading to the inequality

\frac{{p(p - 1)}}{3} < 0

which is satisfied when

p \in (0, 1)

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