JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

\cos ^{-1} x-\cos ^{-1} \frac{y}{2}=\alpha

, then

4 x^{2}-4 x y \cos \alpha+y^{2}

is equal to

View answer and explanation

Correct option: C

4 \sin ^{2} \alpha

Option C (

4 \sin ^{2} \alpha

) is correct because after applying the cosine subtraction formula and simplifying, the expression equals

4 \sin^2 \alpha

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x

{x^2} + {y^2} + {z^2} = {r^2},

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)