JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1

Let

\alpha

and

\beta

are roots of the equation

x^2-6 x+12=0

. The value of the expression

(\alpha-2)^{12}+\frac{(\beta-6)^{12}}{\alpha^{12}}-1

is:

View answer and explanation

Correct option: C

2^{12}

Option C (

2^{12}

) is correct because the expression simplifies to

8^4

after substituting the roots of the quadratic equation and using algebraic manipulations.

More Questions from QUADRATIC EQUATIONS

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{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

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9{x^2} - 18\left| x \right| + 5 = 0

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