JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

\sum\limits_{{i=1}}^{2 n} \sin ^{-1} x_i=n \pi

, then

\sum\limits_{{i=1}}^{2 n} x_i

View answer and explanation

Correct option: B

2 n

Option B (2n) is correct because the sum of inverse sines equaling nπ implies each term must be π/2, leading to each x_i being 1.

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