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JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1

A rectangular coil of wire has dimensions

0.2 \mathrm{~m} \times 0.1 \mathrm{~m}

. The coil has 2000 turns. The coil rotates in a magnetic field about an axis parallel to its length and perpendicular to the magnetic field of

0.02 \mathrm{~Wb} \mathrm{~m}^{-2}

. The speed of rotation of the coil is

4200 \mathrm{rpm}

. Calculate

(i) the maximum value of the induced emf in the coil

(ii) the instantaneous value of induced emf when the plane of the coil has rotated through an angle of

30^{\circ}

from the initial position.

View answer and explanation

Correct option: B

1760 \mathrm{~V}

Option B (1760 V) is correct because it represents the instantaneous induced EMF when the coil has rotated through 30 degrees, calculated using the formula ε = ε_0 sin(wt).

More Questions from ELECTRO MAGNETIC INDUCTION

Practice All Chapter MCQs →

The current in a long solenoid of radius

R

n

turns per unit length is given by

i=i_0 \sin \omega t

. A coil having

N

turns is wound around it near the centre. Find the induced emf in the coil. The induced emf can be produced in a coil by

A. moving the coil with uniform speed inside
uniform magnetic field

B. moving the coil with non uniform speed inside
uniform magnetic field

C. rotating the coil inside the uniform magnetic
field

D. changing the area of the coil inside the uniform
magnetic field

Choose the correct answer from the options given
below: An inductance coil have the time constant

4 \mathrm{sec}

, if it is cut into two equal parts and connected parallel then new time constant of the circuit- If the coils of a transformer are made up of thick wire, then A loop of area

0.1\,\,{m^2}

rotates with a speed of

\mathrm{60}

rps perpendicular to a magnetic field of

\mathrm{0}\mathrm{.4}\,\,\mathrm{T}

\mathrm{100}

turns in the loop, maximum voltage induced in the loop is A

\mathrm{50}\,\,\mathrm{mH}

coil carries a current of

\mathrm{2 A}

, the energy stored in joule is