JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

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Analyzing +4 | -1

The solution set of the in equation

\left| {x + \frac{1}{x}} \right| < 4,

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Correct option: A

\left( {2 - \sqrt 3 ,\;2 + \sqrt 3 } \right) \cup \left( { - 2 - \sqrt 3 ,\; - 2 + \sqrt 3 } \right)

Option A (

\left( {2 - \sqrt 3 ,\;2 + \sqrt 3 } \right) \cup \left( { - 2 - \sqrt 3 ,\; - 2 + \sqrt 3 } \right)

) is correct because it represents the solution set obtained by solving the inequality

\left| {x + \frac{1}{x}} \right| < 4

by considering both positive and negative cases and finding the intersection of the solution sets.

More Questions from QUADRATIC EQUATIONS

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{x^2} + 4ax + 2 > 0

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9{x^2} - 18\left| x \right| + 5 = 0

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