JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

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Application +4 | -1

If two equations

{a_1}\;{x^2} + {b_1}\;x + {c_1} = 0

and

{a_2}{x^2} + {b_2}x + {c_2} = 0

have a common root, then the value of

\left( {{a_1}{b_2} - {a_2}{b_1}} \right)\left( {{b_1}{c_2} - {b_2}{c_1}} \right),

View answer and explanation

Correct option: D

{\left( {{a_1}{c_2} - {c_1}{a_2}} \right)^2}

Option D (

{\left( {{a_1}{c_2} - {c_1}{a_2}} \right)^2}

) is correct because the condition for a common root leads to this relationship between the coefficients.

More Questions from QUADRATIC EQUATIONS

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{x^2} + 4ax + 2 > 0

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a

f\left( x \right) = a{x^2} + bx + c\;

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9{x^2} - 18\left| x \right| + 5 = 0

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