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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy
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Application +4 | -1
Let for a,a1≠0,a≠a1a, a_1 \neq 0, a \neq a_1 f(x)=ax2+bx+c,g(x)=a1x2+b1x+c1f(x)=a x^2+b x+\mathrm{c}, g(x)=a_1 x^2+b_1 x+c_1 and p(x)=f(x)−g(x)p(x)=f(x)-g(x). If p(x)=0p(x)=0 only for x=−1x=-1 and p(−2)=2p(-2)=2, then the value of p(2)p(2) is
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Correct option: D
18
Option D (18) is correct because the given conditions allow us to express p(x) as k(x+1)2, solve for k using p(-2)=2, and then evaluate p(2).

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