JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

{y^2} + {\log _e}({\cos ^2}x) = y,\,\,x \in \left( { - \frac{\pi }{2},\,\frac{\pi }{2}} \right),

then

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Correct option: C

|y''(0)| = 2

Option C (

\left| y''(0) \right| = 2

) is correct because differentiating the given equation and evaluating at x=0 yields |y''(0)| = 2.

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