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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1
The number of real solutions of the equation (5+26)x2−3+(5−26)x2−3=10,{\left( {5 + 2\sqrt 6 } \right)^{{x^2} - 3}} + {\left( {5 - 2\sqrt 6 } \right)^{{x^2} - 3}} = 10, is
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Correct option: B
4
Option B (4) is correct because solving the given equation by recognizing the reciprocal relationship leads to four real solutions for x.

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