JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

\frac{d}{d x}\left[\cos \left(1-x^{2}\right)^{2}\right]

is equal to

View answer and explanation

Correct option: C

4 x\left(1-x^{2}\right) \sin \left(1-x^{2}\right)^{2}

The correct answer is C (

4 x(1-x^{2}) \sin (1-x^{2})^{2}

) because it is the result of applying the chain rule multiple times to differentiate the given function.

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x

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y = {\sec ^{ - 1}}\left[ {\mathrm{cosec}x} \right] + \mathrm{cose}{\mathrm{c}^{ - 1}}\left[ {\sec x} \right] + {\sin ^{ - 1}}[\cos x] + {\cos ^{ - 1}}[\sin x],

\frac{{dy}}{{dx}}

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