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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
1 of 1
Application +4 | -1
If f(x)={x−5  for  x≤14x2−9  for  1<x<2, then  f′(2+)=3x+4  for  x≥2f(x) = \left\{ {\begin{array}{llllllllllllllllllll} {x - 5\quad \mathrm{ }\,\,\mathrm{for}\,\,\mathrm{ }x \le 1}\\ {4{x^2} - 9\mathrm{ }\,\,\mathrm{for}\,\,\mathrm{ }1 < x < 2,\mathrm{ }\,\mathrm{then }\,\,f'\left( {{2^ + }} \right) = }\\ {3x + 4\mathrm{ }\,\,\mathrm{for}\,\,\mathrm{ }x \ge 2} \end{array}} \right.
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Correct option: C
3
The correct answer is C (3) because it is the limit of the derivative of the function as x approaches 2 from the right.

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