Skip to main content
Back to WORK-ENERGY-POWER

JEE PHYSICS MCQ: WORK-ENERGY-POWER

1 Medium
1 of 1
Application +4 | -1
The centripetal force required by a 900 kg car that takes a turn of radius 40 m at a speed of 35 kmph is
View answer and explanation
Correct option: A
2115 N
Option A (2115 N) is correct because it is the result of calculating the centripetal force using the formula F = mv²/r, with proper unit conversions.

More Questions from WORK-ENERGY-POWER

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.