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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A body is moving horizontally at a height of 60 m60 \mathrm{~m} has its P.E equal to K.E. Then velocity of that body is (g=10 m/s2)\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)
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Correct option: B
203 m/s20 \sqrt{3} \mathrm{~m} / \mathrm{s}
Option B (203 m/s20 \sqrt{3} \mathrm{~m} / \mathrm{s}) is correct because the velocity is calculated by equating potential and kinetic energies.

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