JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y \sqrt{1-x^2}=k-x \sqrt{1-y^2}

and

y\left(\frac{1}{2}\right)=-\frac{1}{4}

, then

\frac{d y}{d x}

x=\frac{1}{2}

View answer and explanation

Correct option: C

-\frac{\sqrt{5}}{2}

Option C (-

\frac{\sqrt{5}}{2}

) is correct because it is the value of the derivative of y with respect to x at the specified point.

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