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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
Let f1(x)=exf_1(x)=e^x and fn+1(x)=efn(x)f_{n+1}(x)=e^{f_n(x)} for any n≥1,n∈Nn \geq 1, n \in N. Then for any fixed nn, the value of ddxfn(x)\frac{d}{d x} f_n(x) equals :
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Correct option: B
fn(x)fn−1(x)……f2(x)f1(x)f_n(x) f_{n-1}(x) \ldots \ldots f_2(x) f_1(x)
Option B (fn(x)fn−1(x)…f2(x)f1(x)f_n(x) f_{n-1}(x) \ldots f_2(x) f_1(x)) is correct because it is the result of repeatedly applying the chain rule.

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