JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

For what value of

\lambda

the sum of the squares of the roots of

{x^2} + \left( {2 + \lambda } \right)x - \frac{1}{2}\left( {1 + \lambda } \right) = 0

is minimum?

View answer and explanation

Correct option: C

\frac{1}{2}

Option C (

\frac{1}{2}

) is correct because this value of

\lambda

minimizes the sum of the squares of the roots of the given quadratic equation.

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