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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1
If in a Δ  ABC,∠A=tan⁡−12  and  ∠B=tan⁡−13,  \Delta \;ABC,\angle A = {\tan ^{ - 1}}2\;\mathrm{and}\;\angle B = {\tan ^{ - 1}}3,\; then angle CC is equal to
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Correct option: C
π4\frac{\pi }{4}
Option C (π4\frac{\pi }{4}) is correct because by using the property that the sum of angles in a triangle is π\pi and the formula for tan⁡−1x+tan⁡−1y\tan^{-1}x + \tan^{-1}y, we can solve for angle C.

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