JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

\frac{d}{{dx}}\left\{ {{{\sin }^2}\left( {{{\cot }^{ - 1}}\sqrt {\frac{{1 - x}}{{1 + x}}} } \right)} \right\}

equals

View answer and explanation

Correct option: B

\frac{1}{2}

Option B (

\frac{1}{2}

) is correct because after simplifying the expression using trigonometric identities, the derivative is simply

\frac{1}{2}

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