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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Understanding +4 | -1

If

{\sec ^{ - 1}}x = \mathrm{cose}{\mathrm{c}^{ - 1}}y

, then

{\cos ^{ - 1}}\frac{1}{x} + {\cos ^{ - 1}}\frac{1}{y} =

View answer and explanation

Correct option: D

\frac{\pi }{2}

Option D (

\frac{\pi }{2}

) is correct because if

{\sec ^{ - 1}}x = \mathrm{cose}{\mathrm{c}^{ - 1}}y

, then

{\cos ^{ - 1}}(\frac{1}{x}) = {\sin ^{ - 1}}(\frac{1}{y})

, and

{\cos ^{ - 1}}(\frac{1}{y}) + {\sin ^{ - 1}}(\frac{1}{y}) = \frac{\pi }{2}

.

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