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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Application +4 | -1
The reverse bias in a junction diode is changed from 10 v10 \, \mathrm{v} to 25 v25 \, \mathrm{v} then the value of current changes from 30 μA30 \, \mu A to 80 μA80 \, \mu A. The resistance of the junction diode will be [Ω][\Omega]
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Correct option: C
3×1053 \times 10^{5}
Option C (3×1053 \times 10^{5}) is correct because it is calculated using Ohm's law for the change in voltage and current in the diode.

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