In the case of constants ${\rm{\alpha\; and\; \beta }}$ of a transistor

${\rm{\beta }} > {\rm{ }}1,$${\rm{\alpha }} < 1$

${\rm{\alpha }} = {\rm{\beta }}$

JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Understanding +4 | -1

In the case of constants

\mathrm{\alpha\; and\; \beta }

of a transistor

View answer and explanation

Correct option: D

\mathrm{\beta } > \mathrm{ }1,

\mathrm{\alpha } < 1

Option D (

\mathrm{\beta } > \mathrm{ }1,\mathrm{\alpha } < 1

) is correct because in a transistor, alpha (

\alpha

) is the current gain from emitter to collector, which is always less than 1, and beta (

\beta

) is the current gain from base to collector, which is typically greater than 1.