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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1
Let ff and gg be differentiable functions such that f(3)=5,g(3)=7,f′(3)=13,g′(3)=6,f′(7)=2f(3)=5, g(3)=7, f^{\prime}(3)=13, g^{\prime}(3)=6, f^{\prime}(7)=2 and g′(7)=0g^{\prime}(7)=0. If h(x)=(f∘g)(x)h(x)=(f \circ g)(x), then h′(3)h^{\prime}(3) is equal to
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Correct option: C
12
Option C (12) is correct because, by the chain rule, h′(x)=f′(g(x))∗g′(x)h'(x) = f'(g(x)) * g'(x), so h′(3)=f′(g(3))∗g′(3)=f′(7)∗6=2∗6=12h'(3) = f'(g(3)) * g'(3) = f'(7) * 6 = 2 * 6 = 12.

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