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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Let f(x+y)=f(x)+f(y)f\left( {x + y} \right) = f\left( x \right) + f\left( y \right) and f(x)=x2g(x)f\left( x \right) = {x^2}g\left( x \right) for all x,y∈Rx,y \in R, where g(x)g\left( x \right) is continuous function. Then, f′(x)f'\left( x \right) is equal to
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Correct option: D
0
Option D (0) is correct because, given f(x+y) = f(x) + f(y) and f(x) = x²g(x), it implies f(x) = 0 for all x, thus f'(x) = 0.

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