JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

\frac{d}{{dx}}\left[ {{{\sin }^{ - 1}}(x\sqrt {1 - x} - \sqrt x \sqrt {1 - {x^2})} } \right]

is equal to

View answer and explanation

Correct option: C

\frac{1}{{\sqrt {1 - {x^2}} }} - \frac{1}{{2\sqrt {x\left( {1 - x} \right)} }}

Option C (

\frac{1}{{\sqrt {1 - {x^2}} }} - \frac{1}{{2\sqrt {x\left( {1 - x} \right)} }}

) is correct because it represents the derivative of the given expression after applying trigonometric substitution and simplification.

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