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JEE MATHEMATICS MCQ: DIFFERENTIATION

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If f(x)=(log⁡cot⁡xlog⁡cot⁡xtan⁡x)(log⁡tan⁡xlog⁡tan⁡xcot⁡x)−1+tan⁡−14x4−x2,f\left( x \right) = ({\log _{\cot x}}{\log _{\cot x}}\tan x)({\log _{\tan x}}{\log _{\tan x}}\cot {\left. x \right)^{ - 1}} + {\tan ^{ - 1}}\frac{{4x}}{{4 - {x^2}}}, then f′(2)f'\left( 2 \right) is equal to
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Correct option: A
12\frac{1}{2}
Option A (12\frac{1}{2}) is correct because after simplifying the function and differentiating, the value of the derivative at x=2 is 12\frac{1}{2}.

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