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JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy
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Analyzing +4 | -1
Let f:R→Rf: R \rightarrow R be a function. We say that ff has

Property 1: If lim⁔h→0f(h)āˆ’f(0)∣h∣\lim\limits _{h \rightarrow 0} \frac{f(h)-f(0)}{\sqrt{|h|}} exists and is finite.
and,
Property 2: If lim⁔h→0f(h)āˆ’f(0)h2\lim _{h \rightarrow 0} \frac{f(h)-f(0)}{h^2} exists and is finite.

Then which of the following option is correct?
View answer and explanation
Correct option: B
f(x)=x2/3f(x)=x^{2 / 3} has Property 1
Option B is correct because the limit lim⁔h→0f(h)āˆ’f(0)∣h∣\lim_{h \rightarrow 0} \frac{f(h)-f(0)}{\sqrt{|h|}} exists and is finite for f(x)=x2/3f(x)=x^{2 / 3}.

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