JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1

{x^2} + {y^2} = t - \frac{1}{t}

and

{x^4} + {y^4} = {t^2} + \frac{1}{{{t^2}}}

, then

{x^3}y\frac{{dy}}{{dx}}

equals

View answer and explanation

Correct option: B

The correct answer is 1 because after simplifying the given equations and differentiating,

{x^3}y\frac{{dy}}{{dx}}

equals 1.

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