JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

Let

g\left( x \right)

be the inverse of the function

f\left( x \right)

and

f'\left( x \right) = \frac{1}{{1 + {x^3}}}

then,

g'\left( x \right)

is equal to

View answer and explanation

Correct option: C

1 + {\left( {g\left( x \right)} \right)^3}

Option C (

1 + {\left( {g\left( x \right)} \right)^3}

) is correct because it is derived from the inverse function differentiation rule, where

g'(x) = 1/f'(g(x))

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x

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\frac{{dy}}{{dx}}

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