JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Hard

1 of 1

Application +4 | -1

\alpha, \beta

are the roots of the equation

\mathrm{ax}^2+\mathrm{bx}+\mathrm{c}=0

and

\mathrm{S}_{\mathrm{n}}=\alpha^{\mathrm{n}}+\beta^{\mathrm{n}}

, then a

\mathrm{S}_{\mathrm{n}+1}+\mathrm{c} \mathrm{S}_{\mathrm{n}-1}=

View answer and explanation

Correct option: D

-\mathrm{bS}_{\mathrm{n}}

Option D (-bS_n) is correct because by substituting the roots into the original equation and manipulating the expression, it simplifies to -bS_n.

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