JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

Let

x(t)=2 \sqrt{2} \cos t \sqrt{\sin 2 t}

and

y(t)=2 \sqrt{2} \sin t

\sqrt{\sin 2 t}, t \in\left(0, \frac{\pi}{2}\right)

. Then

\frac{1+\left(\frac{d y}{d x}\right)^2}{\frac{d^2 y}{d x^2}}

t=\frac{\pi}{4}

is equal to

View answer and explanation

Correct option: D

\frac{-2}{3}

Option D (

\frac{-2}{3}

) is correct because after finding the first and second derivatives and substituting

t = \frac{\pi}{4}

, the expression evaluates to

\frac{-2}{3}

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