JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\left\{x \in R:|x-2|=x^2\right\}=

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Correct option: D

\{1,-2\}

Option D (

\{1,-2\}

) is correct because these are the real solutions obtained by solving the absolute value equation.

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\log _7 \log _5(\sqrt{x+5}+\sqrt{x})=0

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{x^2} - 3x + a = 0,a \in R

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\alpha ,\;\beta

{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

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9{x^2} - 18\left| x \right| + 5 = 0

f\left( x \right) = \log \left( {{x^2} - x - 2} \right)