If $ - 1 \le x \le - \frac{1}{2}$, then ${\cos ^{ - 1}}\left( {4{x^3} - 3x} \right)$ equals

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

1 of 1

Application +4 | -1

- 1 \le x \le - \frac{1}{2}

, then

{\cos ^{ - 1}}\left( {4{x^3} - 3x} \right)

equals

View answer and explanation

Correct option: C

- 2\;\pi + 3{\cos ^{ - 1}}x

Option C (

- 2\\;\pi + 3{\cos ^{ - 1}}x

) is correct because by substituting

x = \cos \theta

and considering the given range, the expression simplifies to

3\theta - 2\pi

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x

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2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)