JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Application +4 | -1

A wire loop that encloses an area of

20 \mathrm{~cm}^2

has a resistance of

10 \Omega

. The loop is placed in a magnetic field of

2.4 T

with its plane perpendicular to the field. The loop is suddenly removed from the field. How much charge flows pass a given point in the wire?

View answer and explanation

Correct option: C

4.8 \times 10^{-4} \mathrm{C}

Option C (

4.8 \times 10^{-4} \mathrm{C}

) is correct because the induced charge is calculated using the formula

q = \frac{BA}{R}

, where

B

is the magnetic field,

A

is the area, and

R

is the resistance.

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