JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

\alpha, \beta

and

\gamma

are the roots of the equation

x^3+a x+b

=0

, then

\frac{\alpha^3+\beta^3+\gamma^3}{\alpha^2+\beta^2+\gamma^2}=?

View answer and explanation

Correct option: A

3 b / 2 a

The correct answer is A (

3 b / 2 a

) because

\alpha+\beta+\gamma=0

and

\alpha^3+\beta^3+\gamma^3=3 \alpha \beta \gamma

, which simplifies the expression to

3b/2a

More Questions from QUADRATIC EQUATIONS

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x

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