JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

g(x)=f\left(x-\sqrt{1-x^2}\right)

and

f^{\prime}(x)=1-x^2

then

g^{\prime}(x)

equals to :

View answer and explanation

Correct option: C

2 x\left(x+\sqrt{1-x^2}\right)

Option C (

2 x(x+\sqrt{1-x^2})

) is correct because it is the derivative of g(x) found by applying the chain rule and simplifying.

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