JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Understanding +4 | -1

Let

f

be the function on

[0,1]

given by

f(x)=

x \sin \frac{\pi}{x}

for

x \neq 0

and

f(0)=0

. Then

f

View answer and explanation

Correct option: D

continuous and bounded

Option D (continuous and bounded) is correct because the function

f(x)

is continuous on the interval

[0,1]

and its absolute value is bounded by

|x|

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