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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1
If the equation x2+px+q=0{x^2} + px + q = 0 has roots uu and υυ where p,qp,q are non-zero constants. Then,
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Correct option: A
qx2+px+1=0q{x^2} + px + 1 = 0 has roots 1u\frac{1}{u} and 1v\frac{1}{v}
Option A (qx2+px+1=0q{x^2} + px + 1 = 0 has roots 1u\frac{1}{u} and 1v\frac{1}{v}) is correct because if uu and vv are roots of x2+px+q=0{x^2} + px + q = 0, then the equation with roots 1u\frac{1}{u} and 1v\frac{1}{v} is obtained by substituting x=1yx = \frac{1}{y} in the original equation.

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