JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

The derivative of

{\sin ^{ - 1}}\left( {\frac{{2x}}{{1 + {x^2}}}} \right)

with respect to

{\cos ^{ - 1}}\left( {\frac{{1 - {x^2}}}{{1 + {x^2}}}} \right)

View answer and explanation

Correct option: B

Option B (1) is correct because both expressions simplify to

2 \tan^{-1}x

, making their derivatives equal, and the ratio of the derivatives is 1.

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