JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

If the roots of the equation

\frac{1}{{x + p}} + \frac{1}{{x + q}} = \frac{1}{r}

are equal in magnitude but opposite in sign, then the product of the roots will be

View answer and explanation

Correct option: B

- \frac{{\left( {{p^2} + {q^2}} \right)}}{2}

Option B (

- \frac{{{\left( {{{{p^2} + {q^2}}}} \right)}}}{{{{2}}}}

) is correct because it is the product of the roots calculated using the given condition that the roots are equal in magnitude but opposite in sign.

More Questions from QUADRATIC EQUATIONS

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{\alpha _1},{\beta _1}

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{x^2} + 4ax + 2 > 0

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a

f\left( x \right) = a{x^2} + bx + c\;

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