Current in a coil changes from ${\rm{5}}\,\,{\rm{A}}$ to ${\rm{10}}\,\,{\rm{A}}$ in ${\rm{0}}.{\rm{2}}\,\,{\rm{s}}$. If the coefficient of self-induction is ${\rm{10}}\,\,{\rm{H}}$, then the induced emf is

JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

1 Easy

1 of 1

Application +4 | -1

Current in a coil changes from

\mathrm{5}\,\,\mathrm{A}

\mathrm{10}\,\,\mathrm{A}

\mathrm{0}.\mathrm{2}\,\,\mathrm{s}

. If the coefficient of self-induction is

\mathrm{10}\,\,\mathrm{H}

, then the induced emf is

View answer and explanation

Correct option: B

\mathrm{250}\,\,\mathrm{V}

Option B (

\mathrm{250}\,\mathrm{V}

) is correct because it's calculated directly using the formula for induced emf,

e = L \frac{{dI}}{{dt}}

Practice All Chapter MCQs →

R

n

i=i_0 \sin \omega t

N

4 \mathrm{sec}

0.1\,\,{m^2}

\mathrm{60}

\mathrm{0}\mathrm{.4}\,\,\mathrm{T}

\mathrm{100}

\mathrm{50}\,\,\mathrm{mH}

\mathrm{2 A}