JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

f\left( x \right) = \sqrt {1 - \sin 2x}

, then

f'\left( x \right)

equals

View answer and explanation

Correct option: C

- \left( {\cos x + \sin x} \right),

for

x \in \left( {0,\pi /4} \right)

Option C (

- \left( {\cos x + \sin x} \right)

, for

x \in \left( {0,\pi /4} \right)

) is correct because it accounts for the absolute value and the interval in which the derivative is being evaluated.

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