The correct relation between the two current gains $\alpha \;{\rm{and}}\;\beta $ in a transistor is

${\rm{\alpha }} = \frac{{\rm{\beta }}}{{1 + {\rm{\beta }}}}$

${\rm{\beta }} = \frac{{\rm{\alpha }}}{{1 + {\rm{\alpha }}}}$

${\rm{\alpha }} = \frac{{\rm{\beta }}}{{1 - {\rm{\beta }}}}$

${\rm{\alpha }} = \frac{{1 + {\rm{\beta }}}}{{\rm{\beta }}}$

JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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Understanding +4 | -1

The correct relation between the two current gains

\alpha \;\mathrm{and}\;\beta

in a transistor is

View answer and explanation

Correct option: C

\mathrm{\alpha } = \frac{\mathrm{\beta }}{{1 + \mathrm{\beta }}}

Option C (

\mathrm{\alpha } = \frac{\mathrm{\beta }}{{1 + \mathrm{\beta }}}

) is correct because it represents the correct relationship between the common-emitter current gain (

\beta

) and the common-base current gain (

\alpha